Integrand size = 26, antiderivative size = 119 \[ \int x^8 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {a^2 \left (a+b x^3\right )^5 \sqrt {a^2+2 a b x^3+b^2 x^6}}{18 b^3}-\frac {2 a \left (a+b x^3\right )^6 \sqrt {a^2+2 a b x^3+b^2 x^6}}{21 b^3}+\frac {\left (a+b x^3\right )^7 \sqrt {a^2+2 a b x^3+b^2 x^6}}{24 b^3} \]
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Time = 0.06 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {1369, 272, 45} \[ \int x^8 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \left (a+b x^3\right )^7}{24 b^3}-\frac {2 a \sqrt {a^2+2 a b x^3+b^2 x^6} \left (a+b x^3\right )^6}{21 b^3}+\frac {a^2 \sqrt {a^2+2 a b x^3+b^2 x^6} \left (a+b x^3\right )^5}{18 b^3} \]
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Rule 45
Rule 272
Rule 1369
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \int x^8 \left (a b+b^2 x^3\right )^5 \, dx}{b^4 \left (a b+b^2 x^3\right )} \\ & = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \text {Subst}\left (\int x^2 \left (a b+b^2 x\right )^5 \, dx,x,x^3\right )}{3 b^4 \left (a b+b^2 x^3\right )} \\ & = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \text {Subst}\left (\int \left (\frac {a^2 \left (a b+b^2 x\right )^5}{b^2}-\frac {2 a \left (a b+b^2 x\right )^6}{b^3}+\frac {\left (a b+b^2 x\right )^7}{b^4}\right ) \, dx,x,x^3\right )}{3 b^4 \left (a b+b^2 x^3\right )} \\ & = \frac {a^2 \left (a+b x^3\right )^5 \sqrt {a^2+2 a b x^3+b^2 x^6}}{18 b^3}-\frac {2 a \left (a+b x^3\right )^6 \sqrt {a^2+2 a b x^3+b^2 x^6}}{21 b^3}+\frac {\left (a+b x^3\right )^7 \sqrt {a^2+2 a b x^3+b^2 x^6}}{24 b^3} \\ \end{align*}
Time = 0.75 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.13 \[ \int x^8 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {x^9 \left (56 a^5+210 a^4 b x^3+336 a^3 b^2 x^6+280 a^2 b^3 x^9+120 a b^4 x^{12}+21 b^5 x^{15}\right ) \left (\sqrt {a^2} b x^3+a \left (\sqrt {a^2}-\sqrt {\left (a+b x^3\right )^2}\right )\right )}{504 \left (-a^2-a b x^3+\sqrt {a^2} \sqrt {\left (a+b x^3\right )^2}\right )} \]
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Result contains higher order function than in optimal. Order 9 vs. order 2.
Time = 0.17 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.35
method | result | size |
pseudoelliptic | \(\frac {\operatorname {csgn}\left (b \,x^{3}+a \right ) \left (b \,x^{3}+a \right )^{6} \left (21 b^{2} x^{6}-6 a b \,x^{3}+a^{2}\right )}{504 b^{3}}\) | \(42\) |
gosper | \(\frac {x^{9} \left (21 b^{5} x^{15}+120 a \,b^{4} x^{12}+280 a^{2} b^{3} x^{9}+336 a^{3} b^{2} x^{6}+210 a^{4} b \,x^{3}+56 a^{5}\right ) {\left (\left (b \,x^{3}+a \right )^{2}\right )}^{\frac {5}{2}}}{504 \left (b \,x^{3}+a \right )^{5}}\) | \(80\) |
default | \(\frac {x^{9} \left (21 b^{5} x^{15}+120 a \,b^{4} x^{12}+280 a^{2} b^{3} x^{9}+336 a^{3} b^{2} x^{6}+210 a^{4} b \,x^{3}+56 a^{5}\right ) {\left (\left (b \,x^{3}+a \right )^{2}\right )}^{\frac {5}{2}}}{504 \left (b \,x^{3}+a \right )^{5}}\) | \(80\) |
risch | \(\frac {\sqrt {\left (b \,x^{3}+a \right )^{2}}\, b^{5} x^{24}}{24 b \,x^{3}+24 a}+\frac {5 \sqrt {\left (b \,x^{3}+a \right )^{2}}\, b^{4} a \,x^{21}}{21 \left (b \,x^{3}+a \right )}+\frac {5 \sqrt {\left (b \,x^{3}+a \right )^{2}}\, a^{2} b^{3} x^{18}}{9 \left (b \,x^{3}+a \right )}+\frac {\sqrt {\left (b \,x^{3}+a \right )^{2}}\, a^{5} x^{9}}{9 b \,x^{3}+9 a}+\frac {5 \sqrt {\left (b \,x^{3}+a \right )^{2}}\, b \,a^{4} x^{12}}{12 \left (b \,x^{3}+a \right )}+\frac {2 \sqrt {\left (b \,x^{3}+a \right )^{2}}\, a^{3} b^{2} x^{15}}{3 \left (b \,x^{3}+a \right )}\) | \(178\) |
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Time = 0.24 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.48 \[ \int x^8 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {1}{24} \, b^{5} x^{24} + \frac {5}{21} \, a b^{4} x^{21} + \frac {5}{9} \, a^{2} b^{3} x^{18} + \frac {2}{3} \, a^{3} b^{2} x^{15} + \frac {5}{12} \, a^{4} b x^{12} + \frac {1}{9} \, a^{5} x^{9} \]
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\[ \int x^8 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\int x^{8} \left (\left (a + b x^{3}\right )^{2}\right )^{\frac {5}{2}}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 114, normalized size of antiderivative = 0.96 \[ \int x^8 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {{\left (b^{2} x^{6} + 2 \, a b x^{3} + a^{2}\right )}^{\frac {5}{2}} a^{2} x^{3}}{18 \, b^{2}} + \frac {{\left (b^{2} x^{6} + 2 \, a b x^{3} + a^{2}\right )}^{\frac {7}{2}} x^{3}}{24 \, b^{2}} + \frac {{\left (b^{2} x^{6} + 2 \, a b x^{3} + a^{2}\right )}^{\frac {5}{2}} a^{3}}{18 \, b^{3}} - \frac {3 \, {\left (b^{2} x^{6} + 2 \, a b x^{3} + a^{2}\right )}^{\frac {7}{2}} a}{56 \, b^{3}} \]
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Time = 0.29 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.88 \[ \int x^8 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\frac {1}{24} \, b^{5} x^{24} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {5}{21} \, a b^{4} x^{21} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {5}{9} \, a^{2} b^{3} x^{18} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {2}{3} \, a^{3} b^{2} x^{15} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {5}{12} \, a^{4} b x^{12} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {1}{9} \, a^{5} x^{9} \mathrm {sgn}\left (b x^{3} + a\right ) \]
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Timed out. \[ \int x^8 \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx=\int x^8\,{\left (a^2+2\,a\,b\,x^3+b^2\,x^6\right )}^{5/2} \,d x \]
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